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Tea Break Challenge

03/26/2008 3:54 AM

How old are you, Hillary?


I'm 35


But you've been 35 for years


Yes, but this time it's true. I'm just ignoring the weekends.


How old is Hillary?

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#1

Re: Tea Break Challenge

03/26/2008 6:05 AM

I'll blunder in with 49, but maybe leap-years mess it up.

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#4
In reply to #1

Re: Tea Break Challenge

03/26/2008 9:42 AM

Like you said!

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#9
In reply to #4

Re: Tea Break Challenge

03/27/2008 2:14 AM

One of my (many) sisters is called Hilary, so I can in fact opine on this matter with some certainty. She's somewhere between 35 and 49, but I'm buggered if can remember exactly. I know her birth-date, but I forgot to send her a card anyway.

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#30
In reply to #4

Re: Tea Break Challenge

03/31/2008 5:27 AM

PlbMak,

I never did get the answer to the challenge you sent in on 27 March (I think it was you!).

Picture: 'Steel grey plate with dimples and what looked like an 'H' in red'......what on earth was it?

Just a thought...when these are submitted, it would help if they had advancing numbers. I tried going thru' the CR4 General section, to find the answer.......but horror of horrors, there were dozens all with the same title 'Tea Break Challenge'.

Nevertheless, it is good fun anyway, keep it up.

Ray

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#31
In reply to #30

Re: Tea Break Challenge

03/31/2008 6:15 AM

http://cr4.globalspec.com/thread/19386

Click on PlbMak's name, and then click on "Threads and Blog entries by PlbMak".

Hey, he's got another one ! Must dash.............

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#2

Re: Tea Break Challenge

03/26/2008 6:32 AM

Is long weekends also ignored? If so in what country?

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#3

Re: Tea Break Challenge

03/26/2008 9:27 AM

35*7/5=49

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#5

Re: Tea Break Challenge

03/26/2008 10:12 AM

It depends on what her definition of "is" is.

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#6

Re: Tea Break Challenge

03/26/2008 1:48 PM

How old is Hillary?

53.

35 in hexadcimal is 53 in base 10.

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#7
In reply to #6

Re: Tea Break Challenge

03/26/2008 11:56 PM

Reminds me of the old joke about the 10 types of people in the world, those that understand binary and those that don't.

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#8

Re: Tea Break Challenge

03/27/2008 12:41 AM

chaterpilar How old are you, Hillary?

Age doesn't make any difference unless you're cheese!

My age, why 29! What would make you think otherwise. per H. R. Clinton, prevaricator extraordinary!

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#10

Re: Tea Break Challenge

03/27/2008 5:03 AM

Hmmm,

49 SEEMS the logical answer ... somehow I bet its not that simple

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#11
In reply to #10

Re: Tea Break Challenge

03/27/2008 7:41 AM

it is that simple...49 is the answer .....

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#12

Re: Tea Break Challenge

03/27/2008 7:51 AM

chaterpilar Thanks for posting the answer and ending the speculation and even a correct answer amid the chaos of 'sa' replies.

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#13

Re: Tea Break Challenge

03/27/2008 10:22 AM

Hillary is 45.

35 years has 3,640 weekend days, adding in 16 for leap years, 3,656 days, which is approximately 10 years. 35 + 10 = 45.

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#14
In reply to #13

Re: Tea Break Challenge

03/27/2008 5:36 PM

With 16 leap years, 35 years = 35.365 + 16 = 12791 days = 1827 weeks + 2 days.

1827 weeks + 2 days = 3654 or 3656 lost days. lost days = doh, do I add leap days back in for years...

I'm sure that's not how I did it at #1.

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#15

Re: Tea Break Challenge

03/27/2008 5:55 PM

60

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#16

Re: Tea Break Challenge

03/27/2008 6:48 PM

21

Cause Women only age once their daughters catch up to them?

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#17

Re: Tea Break Challenge

03/27/2008 10:09 PM

My wife has been 27 for nine years now. She's 27, OK. But She doesn't get that the longer she's 27 the more it makes me a dirty old man.

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#18

Re: Tea Break Challenge

03/27/2008 11:05 PM

Hi, chaterpilar!

How did you arrive at 49 again? I took the number of weekends in 35 years and converted them to extra days to add on to the 35 and got 44 years old.

Mark





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#19

Re: Tea Break Challenge

03/28/2008 12:54 AM

I worked backwards from 49, and it verified. I also worked from 35, and came up with 45.

I bet it involves either a looping or recursive algorithm.

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#20
In reply to #19

Re: Tea Break Challenge

03/28/2008 1:35 AM

Hi, 3Doug!

I though about adding in the extra days on leap years, but decided against it, because a person only ages from year to year and leap years might not occur on the weekends.

But, to be fair to myself, I guess that [since she COULD be 45 within either 10 days or 354 days by ignoring the leap years,] depending on her birthday, 45 is correct too.

Ummm, assuming that calculating the answer this way makes any sense.

Mark

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#21
In reply to #20

Re: Tea Break Challenge

03/28/2008 11:06 AM

Why you get the year as a basis for the calculation? Why bother with irregularities of leap years and the like? There is one constant cycle that has been unaltered and unshifted for a couple of millenia and this is the period of 7 days called "a week". It survived through calendar revisions by Julius Ceasar and Pope Gregorius, it survived all leap days since now and generally is immune to all complexity of the calendar. So the ratio between the time intervals measured in the two ways is as simple as 5/7.

One can argue that this is exactly so when assessing time intervals rounded up as multiples of the week. But in a span of about half a lifetime, I don't think we should bother... So indeed it is 35*7/5=49.

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#22
In reply to #21

Re: Tea Break Challenge

03/28/2008 12:31 PM

Hi, tkot!

Big Julie, the number of days in a week, and some pope aside, you're quite correct about the number being 49.

The figure of 45 was arrived at by counting only the number of weekends in the false age of 35 and adding them on.

Correctly, that doesn't determine the greater number of weekends in the true age, which should be the number added on, and which 7/5 would provide.

Mark

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#23
In reply to #20

Re: Tea Break Challenge

03/28/2008 1:36 PM

Out of every seven leap years, one extra day is on a Saturday and one is a Sunday. There are just about two and one-half of these cycles in Hillary's 35 year span, so I calculated 2xSat., 2xSun, and added 1 more for a total of 5 days. Eventually you end up with a few more, but it's not a significant increase.

There are 52 weeks in each year, each having one Sat. and one Sun., for a total of 104 days. If you multiply that number times the 35 years we know Hillary has been with us, you get 3,064, plus the leap year 5 = 3,069. Again, Hillary's true age will add a few more days, but again clearly not a significant increase.

Dividing by the number of days per year, for this purpose, 365 should be close enough, you get just under 10 years, which, when added to the 35 years Hillary lays claim to, means on her next (or most recent past) birthday anniversary, she is/will be 45 - in human years - in dog years, she'd be a museum piece.

I don't get this 7/5ths business at all - where does that make sense? The question is how many weekend days are left out of 35 years to add up to enough years to equal Hillary's true age, not how many weekend days there are in that true age.

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#24
In reply to #23

Re: Tea Break Challenge

03/28/2008 2:31 PM

Hi, Enviorman!

At first I didn't get it either. Then I realized that calculating the time Hillary admits to being alive and finding out her age by that method (which was my immediate first approach) only deals with the age she is lying about.

There might be actually more weekends in her true age than the number in the age she is lying about. So we have to ignore the information contained within the lie and concentrate on only the weekends, which are 2/7 of the week.

That's why we take the false age and multiply it by the simplistic improper fraction to arrive at a more accurate number of weekend added age dates. She confesses that she's 7/5 older than she admits to, not just 35 times the number of weekend days in her make-believe age added to the false age.

It's confusing, I know. But I think the 7/5 analogy is appropriate.

Mark

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#25
In reply to #23

Re: Tea Break Challenge

03/28/2008 2:48 PM

Edit: Mark posted his reply while I was composing mine. I'll let it stand because of the additional info I present.

What about the weekends in the 10 additional years you found? Hillary is not counting those either. But if you figure the uncounted weekends in 45 years, you come up with a final result in the upper 50's.

Remember, I said I worked backwards form 49 to reach 35. Here's how I did it:

49 x 365.25 = 17897.25 Number of days in 49 years. (Using 365.25 for the number of days a year accounts for leap years with having to deal with them separately.)

17897.25 / 7 = 2556.75 Number of weeks in 49 years.

2556.75 x 2 = 5113.5 Number of weekend days in 49 years.

17897.25 - 5113.5 = 12784.25 Number of weekdays in 49 years.

12784.25 / 365.25 = 35.

The 7/5 factor is the ratio of days in the week to weekdays.

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#26
In reply to #25

Re: Tea Break Challenge

03/28/2008 3:35 PM

OK, OK, I don't need to understand it - I will go with an alternate premise - Hillary is female. Hillary SAYS she is 35. Ergo, Hillary's age ≡ 35, no questions, no ifs, no ands, no buts about it. Hillary IS 35!

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#27
In reply to #26

Re: Tea Break Challenge

03/28/2008 4:55 PM

If she gets to be president, it'll be any way she damn well wants, OK !

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#28
In reply to #26

Re: Tea Break Challenge

03/28/2008 7:48 PM

One man said the secret to getting along with his wife was to get in the last 2 words in every conversation. And those words are "Yes, ma'am."

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#29
In reply to #25

Re: Tea Break Challenge

03/29/2008 12:35 AM

Yes 3Doug has it very detailed.

I just did 35 X 7/5..

Cheers.

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