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kkhaliod
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Penstock Pressure

10/18/2011 4:37 PM

How we can calculate the pressure of water in penstock at any Hydro power plant? Any real time example of penstock pressure calculation?
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Tornado
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#1

Re: Penstock Pressure

10/18/2011 4:46 PM

Psi = (head in feet)/2.31

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lyn
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#2
In reply to #1

Re: Penstock Pressure

10/18/2011 7:23 PM

Is this true in the southern hemisphere, as well?
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AussieBob
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#3
In reply to #2

Re: Penstock Pressure

10/18/2011 7:52 PM

We use the special LynDoor inverse manometer which prevents the fluid from falling out.
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lyn
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#4
In reply to #3

Re: Penstock Pressure

10/18/2011 8:32 PM

Thanks for the shameless plug.

LynDoor™Industries is going to send air lift a special gift to you for the unsolicited endorsement of one of our premier products, with sales of over five units last year.

They are on back-order now. Oh the smell of success!!!!!

We'll send it by air. Let us know when if you get it.
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Tornado
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#6
In reply to #2

Re: Penstock Pressure

10/19/2011 12:16 AM

Yes, with a minus sign.

This means that we can let water flow downhill in the Northern Hemisphere, and pipe it horizontally to the Southern. There the water flows uphill, and can be piped horizontally back to the Northern Hemisphere. Energy is extracted both up and down, minus frictional piping losses. I'm surprised DaS Energy hasn't mentioned this yet.

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kkhaliod
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#8
In reply to #1

Re: Penstock Pressure

10/19/2011 5:29 AM

what's about 2.31..??

2.31 is value of which factor..??
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Mikerho
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#9
In reply to #8

Re: Penstock Pressure

10/19/2011 8:09 AM
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lyn
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#10
In reply to #8

Re: Penstock Pressure

10/19/2011 1:48 PM

How about this: 1 foot of regular water will exert 0.43197 PSI on whatever is below it.

You might need a slight correction factor if there are fish swimming in it.

Is this homework, I hope.
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Grand Poobah
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#11
In reply to #8

Re: Pen-stock Pressure

10/19/2011 2:33 PM

1 PSI equals 2.31 Feet of water column, or 2.31 Feet of water column equals 1 PSI. This for a static column of water, with flow in your penstock there will be friction losses that will reduce the PSI by some amount.
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Ried
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#16
In reply to #1

Re: Penstock Pressure

10/20/2011 12:06 PM

Only during static conditions. If there is a flow in the penstock, frictional losses might be a factor to reduce the available pressure. If water is moving at a significant velocity, friction loss is a subtraction from the static pressure.

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dj95401
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#5

Re: Penstock Pressure

10/18/2011 11:24 PM

Why does this smell like a home work assignment? And, how does the Coriolis Effect play into the equation? Or, is this only true when you factor in the Blonde variable?

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leveles
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#7
In reply to #5

Re: Penstock Pressure

10/19/2011 12:33 AM

You are quite correct in asking these refined questions. But, you must realize, these are masters /Phd level subiects, not to be touched by simple undergraduates.

Real life, sir - is not as simple - as you prefer to imagine, if you allow my importunity.
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dj95401
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#14
In reply to #7

Re: Penstock Pressure

10/19/2011 10:40 PM

I guess you just don't get, do you?

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JRaef
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#12

Re: Penstock Pressure

10/19/2011 9:38 PM

All I want to know now is how we figure in the "factor of 11" into this...

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Tornado
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#13
In reply to #12

Re: Penstock Pressure

10/19/2011 9:57 PM

And how about the other factors, 3 and 7? Spooky, huh?

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PWSlack
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#15

Re: Penstock Pressure

10/20/2011 4:17 AM

Pressure of any liquid anywhere is its density multiplied by its depth multiplied by the acceleration due to gravity.

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Users who posted comments:

AussieBob (1); dj95401 (2); Grand Poobah (1); JRaef (1); kkhaliod (1); leveles (1); lyn (3); Mikerho (1); PWSlack (1); Ried (1); Tornado (3)

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