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Relativity and Cosmology

This is a Blog on relativity and cosmology for engineers and the like. You are welcome to comment upon or question anything said on my website (http://www.relativity-4-engineers.com), in the eBook or in the snippets I post here.

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34 comments

Cosmic Balloon Application II: Redshift

Posted June 29, 2009 12:00 AM by Jorrie
Pathfinder Tags: cosmology Redshift

Despite having apparently simple explanations, cosmological redshift remains one of the mysteries of the universe. Neither 'expanding space', nor Doppler shift offer a completely satisfactory answer. Here is a better one (perhaps).

What is cosmological redshift?

It is the observed phenomenon that distant galaxies glow at a redder and redder frequencies the farther out they are. Astronomers measure galactic redshift by comparing the absorption lines of certain elements in the light spectrum of the galaxy to the same light spectrum in the laboratory (or to the spectrum of our Sun). The redshift is then defined as the change in wavelength (Δλ) divided by the laboratory wavelength (λ0) of the absorption line in question, i.e.,

z = Δλ/λ0 = (λ-λ0)/λ0 = λ/λ0 - 1 ----------- (Eq. 1)

where λ is the observed wavelength.

In the expanding cosmic balloon, this is very easily pictured in terms of the ratio of the radius of the balloon now (R0) to its radius (R) at a certain time in the past, i.e.,

z = R0/R - 1 ----------- (Eq. 2)

as shown in Figure 1 (right). Here R0=100 and the red circles represent earlier values of R. It comes directly from Eqs. 1 and 2. It is not difficult to see why wavelength is inversely proportional to the radius. Or is it?

Figure 1 shows the balloon size from around last scattering of photons (the red dot at the origin, R=R0/1089, representing the CMB) up to today (R=R0=100). The red rings are not time based, but size based, at 25%, 50%, 75% of the radius (or circumference) of today. The picture is valid for any expansion profile, provided that there is at least some expansion (also called a perpetual expansion scenario).

Explanations

In the time that the CMB photons were in flight, the balloon expanded by a factor 1089 and the photon wavelengths were 'stretched' by a factor 1089, giving their redshift as: z = λ/λ0 - 1 = 1088. Quite reasonable, it seems at first sight,[1] but how can a photon's wavelength be stretched? A single photon does not even have a defined size, so stretching it is not conceptually very palatable!

Another reasonable explanation may be that it is just different frames of reference between transmission and reception of the photon and that the redshift is a coordinate transformation issue, resulting in Doppler shift. However, the two frames of reference may be moving away from each other at greater than the speed of light in vacuum (c), yet we still measure a real, finite redshift. How do we reconcile this fact with the Doppler shift equations of Einstein, which do not work for recession speeds equal to or larger than c?

So, where does cosmological redshift come from?

The balloon analogy offers a neat 'crutch' that makes the phenomenon a little more palatable. It appears as if photons conserve angular momentum as they travel along the surface of the expanding balloon, almost as if they go into a larger orbit around the center of the balloon.[2] Since photons cannot shed speed in order to keep angular momentum constant in the larger 'orbit', they shed linear momentum in another way - by reducing frequency.

The linear momentum of a photon is given by p = h, where h is the Planck constant. Angular momentum magnitude of a photon relative to the balloon center is given by: R p = R h/λ. If R is increasing, λ must be increasing by the same ratio in order to keep angular momentum constant. Increased λ is the same as cosmological redshift.

I suppose in the end it is not too important which 'crutch' you use - stretching of wavelengths, conservation of angular momentum, or even Doppler shift, as long as it is accepted that the received to emitted photon wavelength ratio (λ/λ0) is the same as the expansion ratio (R0/R) since emission.

Jorrie

[1] See the animation on the Webb Space Telescope site.

[2] This is equivalent to Kepler's second law of planetary motion, stating that a planetary orbit sweeps out equal areas around the Sun in equal time intervals. This is the same as the conservation of orbital angular momentum. The same considerations cause any (massive) particle with a velocity relative to the skin of the balloon to conserve angular momentum and hence slow down, provided that the balloon is expanding. The opposite (speed up) happens if the balloon is shrinking. More about that in a follow-on Blog post.

-J


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#1

Re: Cosmic Balloon Application II: Redshift

06/29/2009 10:02 AM

<Bows respectfully to superguru>

Some time ago there was some discussion that the universe might be toroidal rather than spherical, not that one can ever define such a shape from the outside! Does this impact on the thinking above, or is the toroidal universe concept now passé?

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#3
In reply to #1

Re: Cosmic Balloon Application II: Redshift

06/29/2009 11:06 AM

Hi PWS, no 'supergurus' around anywhere near here!

AFAIK, the WMAP data sets do not support a toroidal cosmos, which is a relief to me, because I have no idea how to model a cosmos based upon it.

-J

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#2

Re: Cosmic Balloon Application II: Redshift

06/29/2009 10:26 AM

Hi Jorrie,

I couldn't get the link from [1] to work, can you check it.

I think it's worth mentioning that the energy of a photon is E=hc/λ meaning that the photon actually has less energy when it arrives then when it started.

Also, I'd like to hear your take on De Broglie waves and gravitational redshift. I've looked around and can't find anything discussing it but it must occur.

Roger

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#4
In reply to #2

Re: Cosmic Balloon Application II: Redshift

06/29/2009 11:20 AM

Hi Roger, tx for pointing out the broken link - fixed it.

Yes, the photons lose both linear momentum and energy as they travel. The 'lost' energy goes into expansion, I guess.

I think De Broglie waves may fit better under the next Blog topic that I'm planning - on particle energies in an expanding cosmos - but yes, there may be a link between the fact that particles lose momentum during cosmic expansion and the redshift of photons. A sort of 'particle redshift' in terms of De Broglie wavelengths. Interesting!

-J

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#5
In reply to #4

Re: Cosmic Balloon Application II: Redshift

06/29/2009 11:28 AM

When we discuss that topic in a future post, let me suggest a less ambiguos approach. There is such a thing as gravitational redshift, right? Why not apply gravitational redshift to a De Broglie wave and see if it agrees with classical escape velocity? It should right? It's just that in one case you treat gravity as curved space that can redshift matter waves and in the other gravity is a force that acts on a massive particle (lowering it's momentum).

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#6
In reply to #5

Re: Cosmic Balloon Application II: Redshift

06/29/2009 11:57 PM

The gravitational redshift would be also be interesting, yes. For this cosmology thread, I'll first try it in the intended context, the reason being that I do not want to mix up the 'cosmic balloon model' and a 'dynamics model' (like the one Jon favors) in this thread. It seems simple enough anyway!

-J

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#7
In reply to #6

Re: Cosmic Balloon Application II: Redshift

06/30/2009 9:13 AM

That makes sense. ok.

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#8
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Re: Cosmic Balloon Application II: Redshift

06/30/2009 8:14 PM

A very 'enlightening' thread! I also bow.

"Yes, the photons lose both linear momentum and energy as they travel. The 'lost' energy goes into expansion, I guess."

Maybe you've discovered the Dark Energy. As the light (photons) get red-shifted they become 'dark'. Do we call this radiation pressure?

-S

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#9
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Re: Cosmic Balloon Application II: Redshift

06/30/2009 8:38 PM

Maybe. What bothers me about this is that no one appears to care. So either the explanation is so obvious (where the photon energy goes) that they (physics community) don't bother to explain it, or the magnitude of energy is so small that it is deemed unimportant (I have a hard time believing that since background radiation fills the entire universe), or no one cares.

It seems like a lot of energy to just ignore.

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#11
In reply to #9

Re: Cosmic Balloon Application II: Redshift

07/01/2009 12:17 AM

Hi Roger, as you noted, I tried to 'illuminate' the issue on my previous reply (to S). As far as the balloon analogy is concerned, there is no problem. In hyperspace, the photons have been 'lifted' to a higher energy plane - remember they lost kinetic energy in order to keep angular momentum constant, but they gained potential energy. That's why I originally blundered in saying "the 'lost energy' went into the expansion". Point is, they were 'lifted higher' by the balloon, not going there on their own accord.

It is somewhat equivalent to a particle orbiting a massive object in an elliptical orbit, continuously trading kinetic energy for potential energy (and visa-versa), while keeping the total mechanical energy constant. We know that photos cannot really orbit like that - even near black holes there is only one orbit, and that is circular and unstable. In the balloon analogy, we just force the photon's hand, so to speak. And so does the universe, apparently.

-J

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#12
In reply to #11

Re: Cosmic Balloon Application II: Redshift

07/01/2009 9:13 AM

Hi Jorrie,

In reply to what you wrote above, to what potential energy are you referring? From the standpoint of within the universe, the photons are losing energy but there is no potential energy gain as far as I can seeunless you are referring to gravitational? Can you clarify?

Also, I was wondering, have there been solutions done for an inhomogeneous universe? I ask not because I believe the universe to be inhomogeneous, but rather because I think it could elucidate local spatial effects. Local space is certainly inhomogeneous.

Roger

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#13
In reply to #12

Re: Cosmic Balloon Application II: Redshift

07/01/2009 11:01 AM

Hi Roger. The potential energy is most definitely gravitational here. Weird as it may seem, photons that are spread out more thinly (less radiation density) possess more potential energy than more dense counterparts. This is because radiation gravitates and it takes work to 'move the photons apart', so to speak. A static 'radiation only' cosmos would have collapsed under its own gravity and hence convert potential energy into shorter wavelength photons again. Perhaps it would disappear into a singularity, perhaps not...

There are various approximations for inhomogeneous universes. Local inhomogeneities are difficult to bring into the model, mostly done through perturbation theory. AFAIK, it is not possible to seamlessly match local solutions to Einstein's filed equations (e.g. the Schwarzschild solution) to the global solution, like Friedman's. I'm not too well clued up on inhomogeneous solutions though.

-J

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#14
In reply to #13

Re: Cosmic Balloon Application II: Redshift

07/01/2009 11:17 AM

Jorrie,

Thanks and Thanks. You're gravitational potential energy explanation seems reasonable. The energy of a photon is proportional to 1/λ (wavelength is just a distance) and the gravitational potential energy between photons is proportional to 1/r.

It feels like cosmic expansion is akin in many ways to a timelike gravitational well, which now that I think about it, is exactly what it is. A space like gravitational well means that as you move away from the well (out of the gravitational potential), the photon is redshifted because it's gravitational potential has increased.

Think about cosmic inflation in a similar way, except instead of moving through space, your moving through time. As time increases you are further and further outside of the gravitational well in the sense that your potential energy has increased, you have redshifted, hell, even the curvature of space has decreased (or is it increasing, I can't seem to get this straight).

How do you feel about such an interpretation Jorrie? It really seems right to me, I hope I'm explaining it well.

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#15
In reply to #14

Re: Cosmic Balloon Application II: Redshift

07/01/2009 1:14 PM

Roger, yes, " ...expansion is akin in many ways to a timelike gravitational well ..."

I'm not too sure what you mean by "timelike" and "spacelike" gravitational wells, but in a sense, the cosmos is expanding out of a gravitational well. There is one proviso though: the center of that well sits in a hyperspace dimension, never in a spatial dimension. The gravitational potential of the homogeneous cosmos is the same everywhere in space. It is only when 'lumpiness' is introduced that you have some local gravitational wells, but these are not part of the LCDM model. It may also be valid to view the gravitational well as sitting in a time dimension, but I am a bit wary of that.

The curvature issue seems to still cause some trouble! Remember that the cosmic balloon does not simulate cosmic curvature at all. The balloon's geometric curvature changes in the wrong sense, but it does not enter into any of the equations used, so it is irrelevant. It is perfectly valid to simulate a flat cosmos (with no curvature at all) by means of a balloon of arbitrary radius - all the calculations work perfectly.

-J

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#16
In reply to #15

Re: Cosmic Balloon Application II: Redshift

07/01/2009 2:45 PM

You wrote:"I'm not too sure what you mean by "timelike" and "spacelike" gravitational wells, but in a sense, the cosmos is expanding out of a gravitational well."

I guess what I was trying to say is not that the cosmos is expanding out of a gravitational well, but rather that it is a gravitational well and as we move forward in time we essentially are moving out of the well. Take a look at the diagram below:

I'm sorry the diagram is so messy. Basically the y-axis is the energy density (in the universe) and the x-axis is time. As we go forward in time the density decreases (as matter and radiation get spread out). Compare this with the gravitational well of a planet and it is very similar, except instead of Time on the x-axis, you would have space (radius r). I hope that makes what I'm trying to say clearer.

For the second part you wrote:"The curvature issue seems to still cause some trouble! Remember that the cosmic balloon does not simulate cosmic curvature at all."

I'm sorry, I wasn't thinking of the cosmic balloon when I was asking, I just couldn't remember which it did (I'm still unclear). In my mind, if big bang was a singularity then it seems like curvature should have decreased since then, but I have the nagging feeling you said that it actually has been increasing, which is why I'm confused.

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#17
In reply to #16

Re: Cosmic Balloon Application II: Redshift

07/01/2009 3:07 PM

To further clarify my point. Imagine we are a photon in space some distance from a black hole. We would expect as we increase our r (distance) from the black hole, that potential energy with respect to that black hole would increase, at the same time we would expect that our wavelength would be redshifted (because we are climbing out of it's gravity well)

I'm saying that this cosmological system is behaving the same way, except that instead of moving through space, the photon is moving through time. (I mean the photon is moving through space as well, but the redshift from cosmic expansion depends only on time). It's as though the Photon feels the gravity from the original singularity through time.

The cosmological constant thus would be a sort of measure against escape velocity of this singularity from back in time. Higher than 0 and the universe expands forever (light redshifts forever as it climbs higher and higher out of the gravity well). Lower than 1 and the universe eventually crashes back together in a big crunch. At 0 it doing neither, but such a position would be unstable.

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#19
In reply to #17

Re: Cosmic Balloon Application II: Redshift

07/01/2009 9:18 PM

Hi again Roger, you wrote: "We would expect as we increase our r (distance) from the black hole, that potential energy with respect to that black hole would increase, at the same time we would expect that our wavelength would be redshifted (because we are climbing out of it's gravity well)"

Qualitatively, yes. Quantitatively, no. The redshift around a black hole scales with √[1-2GM / rc2], while the cosmological redshift scales straight with 1/a, which is equivalent to 1/R for the balloon. So, be careful in not pushing this "analogy" to far - you may get seriously tangled!

"It's as though the Photon feels the gravity from the original singularity through time."

I suppose you can say that, but it's simpler to just consider that all the matter/radiation/vacuum energy of the universe set up a present time gravitational field and that photons and matter particles react to that.

-J

BTW, I've finished the particle 'redshift' (momentum decay) thread and has scheduled it to launch in a few hours from now. I've found the de Broglie wave interpretation very interesting (and have included it), but more difficult to work with than straight relativity.

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#22
In reply to #19

Re: Cosmic Balloon Application II: Redshift

07/01/2009 11:43 PM

Jorrie,

I really appreciating your indulgences on this subject. I want you to know that when you respond I think carefully about what you said, sometimes long after I've responded to you. I feel as though you really are helping me get an understanding of this subject. I'm ordering this book to read up some more.

As for you're caveat about redshift near a black hole, I agree. Lets say the analogy is more accurate the further you get from the black hole (where relativistic effects are less pronounced).

One side question that occurred to me when I was thinking about my timelike singularity (I should probably come up with a different name for this approximation, I'm open to suggestions).

Is there a rotating homogeneous universe cosmic model that you are familiar with? I'm just thinking that it would be an interesting twist (sorry about the pun).

Roger

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#18
In reply to #16

Re: Cosmic Balloon Application II: Redshift

07/01/2009 9:01 PM

Hi Roger, your diagram is just the wrong way round! Density starts out high and decreases as time goes on.

What you describe is akin to the so-called "kinematics model" of the universe. Jon and myself did quite a bit of work on that in this thread. It is useful to some level, but has a few serious problems. (i) It cannot handle the v > c recession velocities of the real cosmos. (ii) It does not agree with the accepted fact that time runs at the same rate everywhere in the homogeneous cosmos.

You must not equate the physical curvature of the balloon with cosmological curvature - they have nothing to do with each other. Cosmic curvature is an energy balance issue - if kinetic energy of expansion equals potential energy, the curvature is zero. If slightly off zero, it diverges farther from zero as time goes on. I have defined this reasonably well in that long thread on the design of the cosmic balloon (in a reply to S).

-J

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#21
In reply to #18

Re: Cosmic Balloon Application II: Redshift

07/01/2009 11:17 PM

Hi Jorrie,

You Wrote:"Hi Roger, your diagram is just the wrong way round! Density starts out high and decreases as time goes on."

You're right of course, sometimes I draw what I'm thinking rather than what I'm saying. What I put in that diagram was how energy density effected space, but I labelled it as energy level. Please disregard that diagram and give me a do over. I really fouled up what I was trying to say with that diagram, let me try again.

Here is a 3D representation of a black hole.

Let's call the position of the Singularity zero. As you move to the right from the singularity you climb out of it (lets not worry for the moment about if that's possible, or start above the event horizon if you can't take the impossibility of what I'm saying).

What I'm trying to say is when you're moving to the right, rather than moving through space, imagine you're moving through time. Each movement to the right is a movement further in time.

I'm saying this because cosmic redshift of radiation behaves exactly like the redshift experienced by a photon climbing out of a gravity well would. This is not the kinematic model you discussed before. This is a hyperspace model. It's just that it's a singularity in time rather than in space.

You Wrote:"You must not equate the physical curvature of the balloon with cosmological curvature"

I never think of the balloon ever when I think about this stuff. Ever.

You Wrote:"Cosmic curvature is an energy balance issue - if kinetic energy of expansion equals potential energy, the curvature is zero."

Lets just drop this. One of the difficulties of communicating by posts is that it's harder for me to assure you that I understand what you're saying. When I say I forgot which way the curvature went, I meant it literally, I just forgot. I remember now, curvature increases as we move forward in time (not smoothly I know).

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#23
In reply to #21

Re: Cosmic Balloon Application II: Redshift

07/02/2009 4:24 AM

Hi Roger, OK, I understand what you are trying here.

BTW: "I never think of the balloon ever when I think about this stuff. Ever." I'm afraid you do not realize what you miss. It's the only no-nonsense way (apart from serious mathematics) that I know of to make sense out of a difficult subject. I still have to find a general case that I cannot explain rather simply using the balloon!

Your "timelike singularity" probably just means that there was a spacetime singularity at some past time. I agree that you should find a better term for your idea. In any case, it does not look much different from the kinematics model, possibly suffering from the same issues that I listed previously.

Your diagram resembles Schwarzschild spacetime geometry. Yes, photons do redshift as they climb out of the gravitational well, but this is gravitational redshift, quite different (technically) from cosmological redshift. Inhomogeneities tend to look like Schwarzschild, but Friedman does not work with inhomogeneities. Good luck if you want to pursue this avenue!

"Is there a rotating homogeneous universe cosmic model that you are familiar with? I'm just thinking that it would be an interesting twist (sorry about the pun)."

No, I have never heard of such a model that works and observations seem to rule it out (we do not see any 'twist').

-J

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#10
In reply to #8

Re: Cosmic Balloon Application II: Redshift

07/01/2009 12:03 AM

Hi S, you wrote: "Maybe you've discovered the Dark Energy. As the light (photons) get red-shifted they become 'dark'. Do we call this radiation pressure?"

I think my "The 'lost' energy goes into expansion, I guess" was maybe a bit misleading.

Photons do not create pressure that can expand the universe - any 'radiation pressure' would have been randomly distributed in all directions and cancel out. Photons simply act as gravitating energy that tries to collapse the universe.

For the first 50 thousand years or so, radiation energy was the dominant energy doing the 'braking' on expansion. Then the radiation energy density dropped lower than the particle energy density and normal matter (light and dark) took over as the 'braking force' on the expansion.

Dark energy only took over some 7 billion years later, both as a 'brake' and as an 'accelerator', with the accelerator winning, it seems. By that time, radiation energy density only made up some .02% of the total energy density, so it made a negligible impression - even less today.

So, where did the 'lost energy' go? OK, maybe still into expansion, but it was never used to cause expansion. Inflation caused the initial expansion (we think) and then the expansion coasted, 'thinning out' all the other energy forms (reducing densities), while keeping the overall total cosmic energy constant.

-J

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#20

Re: Cosmic Balloon Application II: Redshift

07/01/2009 9:40 PM

Jorrie, concerning your link in footnote 1: I like it. Now if only we could convince marcus in the physics forum that space expands. Then maybe we could all get on the same page. Like that's gonna happen. This is another example of the illogicalness that's pervading cosmology these days.

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#24

Re: Cosmic Balloon Application II: Redshift

07/03/2009 6:51 PM

Jorrie, I am making a list of physical & cosmological symbols with their values and definitions after not finding one on the internet, though there probably is one. This paper brought up some questions. The tables on pages 4 and 19 don't quite match with your spreadsheets. Does "Hubble parameter" and "Hubble constant" mean the same thing? What about "cosmological constant" and "vacuum energy density"? I found a good glossary of terms here, and have a good start on the list.

-S

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#25
In reply to #24

Re: Cosmic Balloon Application II: Redshift

07/03/2009 10:25 PM

Hi S, the specialist papers assume that we know a lot of things - there are still some parameters they use that I do not understand and don't care too much about either! The reason is that they do not feature in the Friedman equations - they are useful for observational cosmology only.

Anyway, I think your problem relates to the definition of the Hubble parameter h. Cosmological parameters are generally dimensionless ratios of quantities, with h defined as H0/(100 km/s/Mpc), making it dimensionless, presently taken as h ~ 74/100 = 0.74. The paper you mentioned use 0.73. As you can see, they bring in h2 into some of their parameter values (to eliminate the uncertainty about the value of h somewhat). Divide that into the quoted values and you get more or less what I have in the spreadsheets (which are later values, around 2009 vintage).

The cosmological constant (Λ), vacuum energy density (ρv) and the vacuum energy density parameter (Ωv) are all related, but have different units (and values, of course). To make things more interesting, it's quoted in many different units, e.g. Wikipedia: "Thus, the current standard model of cosmology, the Lambda-CDM model, includes the cosmological constant, which is measured to be on the order of 10−35 s−2, or 10−47 GeV4, or 10−29 g/cm3, or about 10−120 in reduced Planck units."

I prefer it in the "engineering units": Λ ~ 10-2 Gy-2, for that is how I work (there are about 3 x 1016 seconds in a Gy). In SI units, Λ ~ 10-52 m-2, ρv ~ 7.2 x 10-27 kg/m3, with the critical density ρc ~ 9.71 x 10-27 kg/m3, giving Ωv ~ 0.74. Wherever I can, I work only with the dimensionless Ω, but I prefer my Hubble constant as H0/978 Gy-1. Everything either dimensionless or in Gy make sense to me!

-J

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#26
In reply to #25

Re: Cosmic Balloon Application II: Redshift

07/04/2009 12:03 AM

Wikipedia uses H for the Hubble parameter instead of h. Which one is used more? So the paper should have used H0 instead of h and should have called it the Hubble constant instead of the Hubble parameter? That's what I am getting. It's all quite frustrating.

I got the following from this source. What do you think of it?

1. Redshift with Distance

It is a remarkable coincidence that there are actually two ways that you get a redshift with distance (and strangely only the big bang explanation was considered which is the most complicated explanation, the most simple explanation was never considered).

Fig.1 - In Big Bang cosmology, the universe is all that exists, thus to prevent it gravitationally collapsing an expanding universe was proposed. The discovery of the redshift with distance seemed to confirm this, where the redshift is assumed to be a Doppler effect of receding motion due to an expanding universe.
The problems with the Big Bang theory are obvious!

What is a 'Big Bang' and how does it create Space, Time, Matter and Motion?

What is outside the expanding universe?

Fig.2 - In WSM Cosmology, the observable universe is just a finite spherical region of infinite eternal space. We can only see and interact with other matter in this region. Thus there is no need for an expanding universe, as other matter around our observable universe prevents it from collapsing. This is the equivalent of Einstein's Cosmological / Antigravity constant, but it is just normal gravity of matter outside our observable universe within infinite space.
So why the redshift with distance?
Because as we look at matter farther away from us, we find that we share less overlap of a common finite spherical observable universe. And this means that there is less energy exchange, which equates to a redshift with distance.

See The Cosmological Redshift Explained by the Intersection of Hubble Spheres
This article shows that each wave center 'particle' is the center of its finite spherical observable universe (Hubble Sphere) within infinite Space. As two wave center 'particles' move apart there is less overlap of common Hubble spheres / observable universes, thus less wave interactions with increasing distance, thus less energy exchange which then provides a simple sensible explanation of the redshift with distance.

-S

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#27
In reply to #26

Re: Cosmic Balloon Application II: Redshift

07/04/2009 2:43 AM

Hi S,

"Wikipedia uses H for the Hubble parameter instead of h. Which one is used more?"

I don't know which Wiki-article you are referring to, but if that's what it says, it's simply wrong. H is called the 'time varying Hubble constant', also sometimes explicitly denoted by H(t). I do realize that it is sometimes erroneously called the 'Hubble parameter', but the cosmological convention is that a parameter is a dimensionless entity, which H is not. I use the Peebles 1993 conventions. It is also clear that the paper that you referenced last time uses h in the standard way.

I'll respond to the rest of your reply later...

-J

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#29
In reply to #27

Re: Cosmic Balloon Application II: Redshift

07/04/2009 12:23 PM

Hi Jorrie,

I got the H (italicized) from here under the subtitle "Interpretation".

Your Post 25: "Anyway, I think your problem relates to the definition of the Hubble parameter h. Cosmological parameters are generally dimensionless ratios of quantities, with h defined as H0/(100 km/s/Mpc), making it dimensionless, presently taken as h ~ 74/100 = 0.74."

Your post above: "H is called the 'time varying Hubble constant', also sometimes explicitly denoted by H(t). I do realize that it is sometimes erroneously called the 'Hubble parameter', but the cosmological convention is that a parameter is a dimensionless entity, which H is not"

Your post 25 was confusing. Didn't you mean to say that H0 = .74 because it is the one taken at the time of observation? To me it makes sense that H0 would come from H and not h. Also, isn't the italicization part of the 'standard' terminology?

So here is a portion of my list (CR4 editor took out the spaces so I put in dashes):

Symbol - Value --------- Description

H or h -- not constant -- Hubble parameter (time dependent)

H0 -------- 0.74 ---------- Hubble's constant (taken at observation)

Do you not approve?

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#31
In reply to #29

Re: Cosmic Balloon Application II: Redshift

07/04/2009 1:21 PM

Hi S, OK, I see where they confused the two.

Despite a name confusion, the use of H and h are normally very clear. Both H0 and H have the units km/s/Mpc and h is dimensionless, normally reserved for expressing H0 as a dimensionless parameter (a fraction of 100 km/s/Mpc). To make it very clear: if H0 = 74 km/s/Mpc, then h = (74 km/s/Mpc)/(100 km/s/Mpc) = 0.74 (dimensionless). Italicization is normally used for all math symbols in technical texts, so it does not distinguish one symbol from another.

Anyway, your proposed list has it wrong and should rather be:

H or H(t) -- variable (km/s/Mpc) -- Hubble constant (time dependent)

H0 -- presently 74 (km/s/Mpc) -- Hubble's constant at present time

h -- presently 0.74 (dimensionless) -- Hubble parameter at present time.

-J

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#32
In reply to #31

Re: Cosmic Balloon Application II: Redshift

07/04/2009 1:56 PM

I have noticed that the use of the term 'Hubble parameter' for the time varying Hubble constant' (H) is quite widespread, so one must perhaps not be too dogmatic about the name. I see that many call h the 'dimensionless Hubble parameter' to distinguish it from H, although even that is confusing, since h is usually reserved only for the present value of H0/100, not the time varying value (H/100). Prof. Peebles consistently use it as: H0 = 100 h kms/s/Mpc.

Anyway, I haven't seen any equations where it is used incorrectly, despite the apparent name confusion.

-J

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#33
In reply to #31

Re: Cosmic Balloon Application II: Redshift

07/04/2009 7:24 PM

Hi Jorrie,

Thanks for clearing that up. I have changed my list at your recommendation. I'm glad I persevered to avoid confusion later. Now if only I can get MS Word to stop changing h to H, it will be fine!

Here they show a formula or a partial formula in the column labeled symbol. For example, quantum of circulation has h/2me as its symbol. Does that mean it has no symbol? I assume h here is Planck's constant (un-reduced).

-S

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#34
In reply to #33

Re: Cosmic Balloon Application II: Redshift

07/05/2009 12:45 AM

Hi S, you're welcome.

Yes, it does not look as if they have a separate symbol for h/2me. I suppose one has to look at the context to know which h is which!

They also ignored relativistic and cosmological constants and parameters, it seems! I suppose they are not quite 'fundamental'?

J

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#28
In reply to #26

Re: Cosmic Balloon Application II: Redshift

07/04/2009 3:58 AM

Hi again S.

I had a quick look at WSM Cosmology and did not get too far before I got disgruntled by the lack of understanding of what cosmology is all about. So I stopped reading...

Just two examples from the opening page of the website:

- "The universe is expanding (the redshift with distance supports this if it is caused by Doppler shifting due to receding motion - this is the path Cosmology went down)."

- "While the observable universe is finite in both theories, in the Big Bang theory the universe is all there is, whereas in WSM cosmology the observable universe (Hubble Sphere) is just a finite spherical region of infinite eternal space."

I feel these two misunderstandings speak for themselves!

-J

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#30
In reply to #28

Re: Cosmic Balloon Application II: Redshift

07/04/2009 12:32 PM

Hi Jorrie,

I think I could have found worse quotes than the ones you posted. I couldn't make sense of a sphere around a distant particle (like it could observe us). And it said their explanation was the simple one! Ha, yours is far more simple. It has to be if I can understand it! One for the trash can, I think.

-S

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