Velocity Change That Produces 1 G

I've talked about this here before.

what about 1 G not 0.1G

6.55 days at 1G...

Read the last line of my post...

By the way, velocity does not produce 1G, only acceleration can do that. Acceleration of one (1) Standard G: 9.80665 m/s², otherwise known as 0.00980665 Km/s², so it is not much in astrophysical terms.

86,400 seconds per day, thus the daily acceleration is 73,206,249.984 Km/day², and that seems like a whole lot.

Starting at "0" velocity (or speed if you prefer), v=at, thus at the end of one day at 1G the speed would be 73,206,249.984 Km/day, which seems like a hell of a lot. Did I do this wrong?

v=at --> t=86,400, a=G , thus we have also 9.80665 x 86400 = 847,294.56 m/sec at the end of the first day, and that is 73,206,249.984 Km/day. So unless your trip path is a lot longer than this, you might want to think about BRAKING now.

Your math is just wrong, line up against the wall.

Jul 27, 2018 - Earth and Mars are supposed to be 57.6 million Km apart.

Let's aim for that date! We can shave off a couple days.

We just need to get one of these working!

Even assuming it works, it's never going to get anywhere near 10 m/s²

Any rocket that gets off the ground at all achieves that, but none so far has done so for 6.5 days.

Agreed. But that engine (even if it worked) would need a rocket engine (or equivalent) to get it off Earth.

http://www.techtimes.com/articles/11867/20140801/nasa-acknowledges-impossible-fuel-less-drive-may-actually-work.htm

Nobody said anything about arriving or surviving the Martian landing intact. Then there's the uncertain distance between Earth and Mars that will be determined by their position at launch. I almost forgot to mention that unless this arbitrary 1G acceleration limitation gets applied after achieving Earth orbit then nobody is going nowhere. Is this a polar Earth orbit we're launching from or am I just being pedantic to hear myself type.

If there is no requirement for the projectile to arrive intact, then there is no point of putting humans onto it, in which case a different acceleration to 1G could be accommodated.

Pretty much true statements between the bookends. The error introduced while turning the ship about for deceleration might just be enough to allow the spacecraft to arrive at the scene of the crash.

This is just a copy of a previous post http://cr4.globalspec.com/comment/93070/Re-Breaking-the-Speed-of-Light

Why stop at 1g: if you want to go a bit further a field in a reasonable time frame you've got to really up the ante (anti?). First off imagine that you had a rocket powerful enough to accelerate the earth at 2g: if you stood "on the ceiling" in a building at the bottom of this "rocket" you'd experience exactly 1g.

Extending this idea what we need to do is grab a small piece of neutron star and put it in orbit around the sun: you then build the rocket with the mass in the nose and the passengers in a huge lift initially at the bottom, so that the occupants experience 1 g. Now as you gradually increase the acceleration you move the lift closer to the mass in the nose. Once you reach the optimum acceleration the lift stops and the passengers move into the living accommodation. Of course if the power fails for any reason you get squished. When you reach the halfway point of the journey you have to move the lift away from the mass whilst reducing the acceleration, and at the point when you're in free fall you turn the whole thing around and start to increase the deceleration whilst moving the lift back towards the mass. Most of the second half of the journey is spent in constant deceleration.

The picture is the gravitational field generated with a lump of neutron star far out to the left and a constant acceleration of 30 g. the whole shape is rotated about a horizontal (from C to D) axis.

Key to colours:

White less than 0.2 g
Blue 0.2 to 0.9 g
green 0.9 to 1.1 g
salmon 1.1 to 2 g
yellow 2 to 3 g
red 3 to 4 g

The whole thing is scalable so: in a small ship a single passenger might sit with his head just above A and his feet below B; he would be being squashed up from the bottom and down from the top. Or he might sit with his feet at C and head at D in which case he would be being stretched.

But, it would be much more fun with a huge ship with living accommodation all round the area with approximately 1g. If you wanted to get from A to B you could jump through a hole in the floor and should just about get to the other side before you came to rest (relatively). If you wanted to get from C to D you would need to climb "up" towards the centre where you would reach a room in which you could jump off the floor onto the ceiling (making sure to avoid the people shooting past from A to B), you would then climb "down" to D. Finally at C the force is away from the centre and at A it is towards the centre, so, we would need Escher to design the stairs/corridor from C to A.