Converting N/mm2 Into Kilograms

That pair of units is incompatible.

However, there are some pipe flow calculations that could correlate N/mm² pressure drop with something like kg/h flow. Is that what you mean?

THAT IS BETTER

1 m3 = 1000 kg. Is is not?

Only if it's water.

Sorry

The density of LPG at 15C at pressure of 1 bar is 500.0 kg/m3 to 510 kg/m3.

I take average between to and hence, it is 505.0 kg/m3

Density of (a) Commercial Propane at 15c is .51 kg/kg per litre and

(b) Commercial Butane .58 kg/l . So for (a) 510.0 kg/m3 and (b) 580.0 kg/m3.

Sorry read above as (a) .51 kg/L and (b) .58 kg/L

All the values you have given are for liquid!

The OP is asking about gas.

The OP is asking about LPG...Liquified Petroleum Gas

He needs to density value of the mixed phase fluid at his T & P.

My furnace burns LPG, but the Liquid is converted to Gas (boils to Vapor) before it exits the tank. No liquid ever gets anywhere near the furnace. Where does this mixed phase fluid exist?

In the Original Post, he was asking about N/mm², which is a pressure value, and kg, which of course is a mass value, so no conversion possible.

In Post #2, he says NM3 to kg. I suspect that this is referring to Normal m3 (what I would refer to as m³ @ STP (Standard Temperature and Pressure). It could also refer to the normal temperature and pressure at which the fuel is delivered to the furnace. I don't know if STP has the same values in all countries.

If the densities provided by other posters does not answer the question, then we need much more specific information from the OP.

Despite the OP being so short...I read it as a question of mass of gas in a tank/bottle rather than furnace delivery one (and yes, I'd noted the units issue, but that had been dealt with by the time I arrived).

From the linked article, propane has a vapour pressure of 22 bar. It seemed likely to me that the fluid in the tank would be mixed phase - gas and liquid.

As you say, if it's merely a volumetric flow rate to mass flow rate conversion that is required, then the gaseous density values are all that are needed.

When so little information is given, and especially with incorrect units, it is open to lots of different interpretations!

After post #33, we now know it is a flow rate, and I will assume that the N is for Normal, so it would be a gas. If this is the case, then post #5 should have answered the question.

Only if it's liquid.

Dear Mr.ANKUSH JAIN,

Unless the DENSITY and TEMPERATURE of the gas, and FLOW RATE in Cu. Metre is known, it is not possible to calculate the weight of the gas in to Kilograms

DHAYANANDHAN.S

N/mm2 is a pressure while kg is mass. This is like asking how many amps is a Volt/s. Wherever you got that question from, some data has gotten lost on the way. Unless you find out what has gone missing or give more background, no one will be able to answer your question correctly. Good luck.

Please confirm your units Ankush.

I'm guessing you want to convert cubic metres of LPG at normal temperature and pressure (20C and 1 atm) into kilograms of LPG. Do you have some metering issues?

I believe that Mukulmahant was unfairly given an off topic rogering. If Ankush can confirm then M will get a GA from me. Right now he gets an EG (excellent guess) from me.

As noted by M, LPG can be propane or butane and they have different densities.

Actually I have a background guess: LPG, delivered as a liquid, has a vapor pressure higher than atmospheric pressure. This means, it will evaporate if pressure is not maintained in the storage vessel. Consequently, the system has tankside over pressure. The furnace may use a pressure drop at its inlet to regulate flow. In essence a pressure reduction valve at the inlet is set to a certain value. That minus the pressure inside the furnace (atmospheric or very close to it) would be the pressure drop the system is set up for and at which it has it's design flow rate. In order to know the flow rate, one would have to know the relationship between the pressure drop and the flow rate. There are several ways to find that out: 1. Ask the manufacturer, 2. Install a mass flow controller (MFC), 3. base it on theoretical calculation. So if this is the background of your question there are possibilities to relate the two units, that is: Flow rate in kg/h is a function of inlet pressure in N/mm2 Am I on the right track?

Who knows? The OP hasn't responded.

Propane=2Kg/cu.mtr

Butane = 2.6Kg/cu mtr -- Both at NTP

Not 500 Kg /Cu mtr as Ducon repeats

But the Questioner is missing!

He better knows Flowrate into Burners.-Nm3/min or hour

Only then can he get his Kg/Hour Consumption by the Furnace.

Discussions should end here.

Sorry those figures are from the Propane Gas Association Canada

www.propangegas.ca

i never comment on anything not authentic.

Log on: www.propanegas.ca/FileArea/PGAC/Propane%20properties.pdf

or type"propane properties" on google and download Pdf.

Guys, both of you are right! Propane as a gas is the low number at Standart conditions, LPG, so liquid propane, is the high number.

Thanks a heap Tompa.

POSTS #16 AND #38 hold the answer .

Just multiply .

mm

Why is this strand marked off topic????

Probably because I've asked pretty much the same question three times now and haven't got a response.

Ta-da!

And you should know (our newbie OP is forgiven this time...) to turn the Off Topic button off before posting....

masu -- You are so Precise!

That is the way to carry out sensible discussions in CR4

Lead us kindly light

mm

Dear Ankush,

Hope above conversion helps you.

Reagads.

Except kg/cm² is not a recognized metric unit.

It basically comes from the old imperial system of measurements where pounds were used to measure both force and mass. That's ok for the most part on earth where the acceleration due to gravity is fairly constant but as soon as you start using accelerations other than g it blows up in your face.

In the metric system Newtons are the units used to measure force while kg are units of mass, therefore mass per area becomes a meaningless measurement.

Unfortunately people that don't understand the metric system simply convert pounds to kilograms (1 pound mass = 0.4537 kg) and square inches to square centimetres ( 1 in² = 6.4516 cm²) and think they have converted an imperial pressure into a metric pressure.

Instead you have to convert pounds force into Newtons ( 1 lb_f ≈ 4.448222 Newtons) and square inches into square metres ( 1 in² ≈ 645.16 x 10^-6 m²). Also instead of using the base units of Newtons per square metre the base unit is named after Blaise Pascal and as such is called a Pascal or Pa for short.

This is not a pressure problem. It is a "quantity" problem.

Regarding the conflicting density figures.....

I have found sources quoting both these figures. They can't both be right?

Will you guys give me a GA on Posts # 12,13 & 17 and close this Title. After # 17 there is nothing else authentic. multiply the /L x 1000 = m3/hr.

I was joking on the GA. Thanks